At Sea Level, Where G=9.80 M/s^2, A Pendulum Has A Period Of 1.000s. When You Take It To The Top Of A (2024)

Answer:

3.3 rad/sec.

Explanation:

The term '' average angular velocity'' can be defined as the rate at which the angular velocity changes. Kindly note that the rate in which the angular velocity changes is in radian per seconds[rad/sec]. So, without mincing words let's dive straight into the solution to the question above.

The radius of the blowing ball = 12cm, the initial angular velocity = 5.0 rad/s, the final angular velocity = 1.5 rad/s and the angle of rotation = 5.5 radians.

Therefore, from the definition of average angular velocity given above, the mathematical representation can be written as given below:

The average angular velocity = [ the initial angular velocity] + [the final angular velocity] / 2.

Thus, the average angular velocity = [ 5.0 rad/s + 1.5 rad/s] / 2 = 3.3 rad/s.

Answer:

yez

Explanation:

Answer:

The work done by the system (engine) is 5179 J

Explanation:

Given;

heat generated by the automobile engine, q = 2283 J

change in internal energy, ΔU = -2896 J

The work done by the system (engine) is given by the formula for estimating change in the internal energy of a system.

ΔU = q - w

-2896 = 2283 - w

w = 2283 + 2896

w = 5179 J

Therefore, the work done by the system (engine) is 5179 J

Answer:

At constant mass, the acceleration of an object varies (directly) with the net external force applied. That is to say, that an object's acceleration increases as the force applied is (increased), but its acceleration decreases if the force applied is (decreased).

Explanation:

Mechanical Force

According to the second Newton's law, the acceleration of an object varies directly proportional to the external net force applied and inversely proportional to the mass of the object.

If the mass is constant, then the acceleration will vary in the same way as the force does.

Completing the sentences:

At constant mass, the acceleration of an object varies (directly) with the net external force applied. That is to say, that an object's acceleration increases as the force applied is (increased), but its acceleration decreases if the force applied is (decreased).

The net force is directly proportional to acceleration at constant mass while the mass is inversely proportional to acceleration at constant force.

According to Newton's second law of motion, at constant mass, the force applied is directly proportional to acceleration. That is; F = ma

F = force

m = mass

a = acceleration.

As such, when the force applied is increased, the acceleration increases. When the force applied is decreased, the acceleration decreases.

To complete the sentence; At constant mass, the acceleration of an object varies (directly, inversely) with the net external force applied. That is to say, that an object's acceleration increases as the force applied is (decreased, increased), but its acceleration decreases if the force applied is (decreased, increased) At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force, a heavier object will experience (less, greater) acceleration than a lighter one.

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Answer:

55 N/kg is the answer I fhink6

Answer:

55kg * 9.81m/s2 = 539.4 N

Explanation:

It depends on the gravitational force pressing downward on them. The formula for this is W = mg, where W is weight (in Newtons), m is the mass of the object (in kilograms), and g is the force of gravity, which is ~9.81 m/s-2 on Earth.

Answer:

14.49 g/cm²

Explanation:

I = Io e^-(ux)

Where:

I = 573

Io = 1045

x = 0.3 inches and

rho = 11.4g/cm^3

Using the conversion constant

1 inch = 2.54 cm;

0.3 inches = 0.3 * 2.54 cm

0.3 inches = 0.762 cm

I/Io = e^-(ux), or say

Io/I = e^(ux), taking the In of both sides

ln(Io/I) = ux, making u subject of formula

u = 1/x * ln(Io/I)

u = 1/0.762 * ln(1045/573)

u = 1.312 * 0.6

u = 0.787

Next, we say that

u/rho = 0.7872/11.4 = 0.069

And finally, we make

1/(u/rho) to be our final answer

Inverse of the answer is = 14.49 g/cm²

Therefore, the um^-1 in g/cm^2? is 14.49

Answer:

The time is [tex]t = 2.595 \ s[/tex]

The speed is [tex]v = 25.43 \ m/s[/tex]

Explanation:

From the question we are told that

The height of the cliff is [tex]h = 33 \ m[/tex]

Generally from kinematic equation we have that

[tex]h = ut + \frac{1}{2} gt^2[/tex]

before the jump the persons initial velocity is u = 0 m/s

So

[tex]33 = 0 * t + \frac{1}{2} 9.8 * t^2[/tex]

=> [tex]t = 2.595 \ s[/tex]

Generally from kinematic equation

[tex]v= u + gt[/tex]

=> [tex]v= 0 + 9.8 * 2.595[/tex]

=> [tex]v = 25.43 \ m/s[/tex]

Answer:

[tex]I_{2}=2.39*10^{-5} W/m^{2}[/tex]

Explanation:

The definition of the intensity in terms of power is given by:

[tex]I=\frac{P}{A}[/tex]

Where:

P is the powerA is the area

If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.

Let's recall the area of a sphere is [tex]A = 4\pi R^{2}[/tex]

To the first location we have:

[tex]I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}[/tex]

and to the second location we have:

[tex]I_{2}=\frac{P}{4\pi 78^{2}}[/tex]

Now, we can divide each intensity to find the second intensity.

[tex]\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}[/tex]

[tex]I_{2}=I_{1}* \frac{22^{2}}{78^{2}}[/tex]

[tex]I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}[/tex]

[tex]I_{2}=2.39*10^{-5} W/m^{2}[/tex]

I hope it helps you!

Answer:

I = 2.4*10⁻⁵ W

Explanation:

By definition the intensity of a sound source, is the power emitted from the source divided by the area of the surface covered by the sound waves.Assuming that the source is a point source, so it emits sound uniformly in all directions, and there are no reflections, this area is just the area of a sphere centered in the point source and with radius equal to the distance between the source and the point where the intensity is measured, as follows:

[tex]I = \frac{P}{4*\pi *r^{2}} (1)[/tex]

If I and r are givens of the problem, we can solve (1) for P, as follows:

[tex]P = I*4*\pi *r^{2} = 3.0e-4*4*\pi * (22m)^{2} = 1.83 W (2)[/tex]

Since the power is the same at any distance from the source, we can obtain the new value of I, replacing in (1) the value of P and the new value of r, as follows:

[tex]I = \frac{P}{4*\pi *r^{2}} = \frac{1.83W}{4*\pi *(78m)^{2}} =2.4e-5 W/m2 (3)[/tex]

Answer:

3449.6 kgm²

Explanation:

Given that

Radius of the merry go round, r = 5.6 m

Mass of the merry go round, M = 140 kg

Mass of the children, m = 40 kg

Total moment of inertia, I = ?

The total moment of inertia is given as the sum of moments of inertia of the merry-go-round in addition to that of the child. Mathematically, we say

I = 1/2Mr² + mr²

I = 1/2 * 140 * 5.6² + 40 * 5.6²

I = 70 * 31.36 + 40 * 31.36

I = 2195.2 + 1254.4

I = 3449.6 kgm²

Therefore, the total moment of inertia of the merry go round and that of the children on it is 3449.6 kgm²

Answer:

the answer is c

Explanation:

Answer:

a

[tex]v = 1.9267 \ m/s[/tex]

b

The value is [tex]\mu = 0.0063[/tex]

Explanation:

From the question we are told that

The mass of the person is [tex]m_1 = 50.3 \ kg[/tex]

The horizontal velocity is [tex]u_1 = 2.44 \ m/s[/tex]

The mass of the shed is [tex]m_2 = 13.4 \ kg[/tex]

The distance covered is [tex]d = 30 \ m[/tex]

Generally from the law of momentum conservation we have that

[tex]m_1 * u_1 + m_2 * u_2 = (m_1 + m_2)v[/tex]

Here [tex]u_2[/tex] is the initial velocity of the shed which is 0 m/s

[tex]50.3 * 2.44 + 13.4 * 0 = (50.3 + 13.4) v[/tex]

=> [tex]v = 1.9267 \ m/s[/tex]

Generally the workdone by friction is mathematically represented as

[tex]W = \Delta KE[/tex]

[tex]W = \frac{1}{2} * m * (v_f - v )[/tex]

Here [tex]v_f[/tex] is the final velocity of the person and the shed when they come to rest and the value is [tex]v_f = 0 \ m/s[/tex]

Generally this workdone by friction is also mathematically represented as

[tex]W = - \mu * m * g * d[/tex]

=> [tex]- \mu * m * g * d = \frac{1}{2} * m * (v_f - v )[/tex]

=> [tex]\mu = - \frac{0.5 * ( v_f^2 - v^2 )}{g * d }[/tex]

=> [tex]\mu =- \frac{0.5 * ( 0^2 - 1.9267^2 )}{9.8 * 30 }[/tex]

=> [tex]\mu = 0.0063[/tex]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

Answer:

The compression of the spring is 0.633 m.

Explanation:

Given;

mass of the skier, m = 70 kg

speed of the skier, v = 4 m/s

spring constant of the spring, k = 2800 N/m

At the bottom of the hill the kinetic energy of the skier will be maximum while the potential energy will be zero, thus all the mechanical energy of the skier will be converted to kinetic energy.

Apply the law of conservation of energy;

the kinetic energy of the skier at the bottom hill = elastic potential energy of the spring.

[tex]\frac{1}{2}mv^2 = \frac{1}{2}kx^2\\\\mv^2 = kx^2\\\\x^2 = \frac{mv^2}{k} \\\\x = \sqrt{\frac{mv^2}{k}}[/tex]

where;

x is compression of the spring

[tex]x = \sqrt{\frac{mv^2}{k}}\\\\x = \sqrt{\frac{(70)(4)^2}{2800}}\\\\x = 0.633 \ m[/tex]

Therefore, the compression of the spring is 0.633 m.

Answer:

People can capture geothermal energy through: Geothermal power plants, which use heat from deep inside the Earth to generate steam to make electricity. Geothermal heat pumps, which tap into heat close to the Earth's surface to heat water or provide heat for buildings

When the weather is cold, the water or refrigerant heats up as it travels through the part of the loop that's buried underground. Once it gets back above ground, the warmed water or refrigerant transfers heat into the building. The water or refrigerant cools down after its heat is transferred.

Answer:

48.7°C

Explanation:

Step one:

given data

Quantity of heat = 4000J

mass of sample= 70g= 0.07kg

initial temperature T1=35°C

Water has a specific heat capacity of 4182 J/kg°C

Required

The final temperature T2

Step two:

Q= mcΔT

4000= 0.07*4182(T2-35)

4000=292.74(T2-35)

4000=292.74T2-10245.9

collect like terms

4000+10245.9=292.74T2

14245.9= 292.74T2

divide both sides by 292.74

T2= 14245.9/ 292.74

T2=48.7°C

The final temperature of the sample will be "48.7°C". To understand the calculation, check below.

Heat and temperaure

According to the question,

Heat quantity, Q = 4000 J

Sample mass, m = 70 g or,

= 0.07 kg

Initial temperature, T₁ = 35°C

Specific heat capacity, c = 4182 J/kg°C

We know the relation,

→ Q = mcΔT

By substituting the values, we get

4000 = 0.07 × 4182 (T₂ - 35)

= 292.74 (T₂ - 35)

= 292 T₂ - 10245.9

Now,

4000 + 10245.9 = 292.74 T₂

14245.9 = 292.74 T₂

T₂ = [tex]\frac{14245.9}{292.74}[/tex]

= 48.7°C

Thus the above answer is correct.

Find out more information about temperature here:

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Answer: B

Explanation:

Answer:

b. positive

Explanation:

A negatively charged object A has excess electron while uncharged object B is neutral, i.e equal number of electrons and protons.

When the negatively charged object A is brought in contact with the neutral object B, the electrons present in object B will be repelled (likes charges repel). This process will leave object B with excess protons, thus object B will positively charged.

The correct option is "B"

Answer:

The answer is "[tex]2.41 \times 10^3[/tex]"

Explanation:

Given:

[tex]m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\[/tex]

Using formula:

[tex]\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}[/tex]

[tex]p_i, p_f[/tex] = system initial and final linear momentum.

[tex]V_i, v_f[/tex] = system original and final linear pace.

[tex]m_i[/tex] = original weight of the car freight.

[tex]m_f[/tex]= car's maximum weight

[tex]= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3[/tex]

[tex]\boxed{m_f = 2.41 \times 10^3}[/tex]

Answer:

82.8 J

Explanation:

The work done to raise the crate is ...

PE = Mgh = (3 kg)(9.8 m/s^2)(2 m) = 58.8 J

The kinetic energy added to send the box flying is ...

KE = (1/2)Mv^2 = (1/2)(3 kg)(4 m/s)^2 = 24 J

So, the total work involved in this activity is ...

58.8 J +24 J = 82.8 J

Answer:

[tex]\rho=333.33\ kg/m^3[/tex]

Explanation:

Given that,

A container is filled with liquid. At a depth of 60 cm it exerts a pressure of 2000 Pa.

We need to find the density of the liquid.

The pressure exerted by liquid at a depth is given by the formula as follows :

[tex]P=\rho gh[/tex]

h = 60 cm = 0.6 m

g is acceleration due to gravity

Putting all the values,

[tex]\rho=\dfrac{P}{gh}\\\\\rho=\dfrac{2000}{10\times 0.6}\\\\=333.33\ kg/m^3[/tex]

So, the density of the liquid is [tex]333.33\ kg/m^3[/tex].

Answer:

No, the isothermal process is the not same as an adiabatic process for an ideal gas.

Explanation:

There is no change in the internal energy of an ideal gas undergoing an isothermal process since the internal energy depends only on the temperature.

But in the adiabatic process, there is no heat transfer, but work transfer can take place which causes the change in the internal energy due to which there is a change in temperature of an ideal gas.

Hence, the isothermal process is the not same as an adiabatic process for an ideal gas.

Answer:

The tension force of the cable is 588 N

Explanation:

Net Force

The Second Newton's law establishes that the acceleration an object has depends on the net force through the equation:

F = m.a

If the net force is zero, then the acceleration is zero, and the object's velocity remains constant.

The crane lifts a 60 Kg load at a constant velocity. It means the net force acting on the load is zero.

There are two forces acting on the load: The weight of the load and the tension of the cable that holds it.

Since the net force is zero, both forces have the same magnitude:

[tex]T = m.g = 60\ kg\cdot 9.8\ m/s^2[/tex]

T=588 N

The tension force of the cable is 588 N

Answer:

B

Explanation:

Taking the accelerating force of the wind into cognisance. We can represent it as the sum of two components:

707 /√2 = 500 N acting north, and

707 /√ 2 = 500 N acting east.

The reason is because it is said to be acting NorthEast wards, so it's acting both to the North and to the East. The eastward component will then cancel that of the westward component of the drag of the keel.

Essentially, the sum of two forces that is acting on the boat will then be equal to 500 N north.

To get the acceleration of the boat, we then divide the force by the given mass such that

500/200 = 2.5 m/s^2 northward.

Answer:The television

Explanation:

Answer:

0.67 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{2}{3} \\ = 0.66666...[/tex]

We have the final answer as

0.67 m/s²

Hope this helps you

Answer:

x = 0.100 cos (3.65 t)

Explanation:

We must solve Newton's second law for this case

F = m a

the spring force is given by Hooke's law

F = -kx

and the definition of acceleration is

a =[tex]\frac{d^2x}{dt^2}[/tex]

let's substitute

- kx = m \frac{d^2x}{dt^2}

\frac{d^2x}{dt^2} + [tex]\frac{k}{m}[/tex] x = 0

this equation has as a solution

x = A cos (wt + Ф)

where

w = [tex]\sqrt{\frac{k}{m} }[/tex]

let's calculate

w = [tex]\sqrt{\frac{20}{1.5} }[/tex]

w = 3.65 rad / s

to find the constant fi let's use the condition t = 0 x = 10.0 cm

x = A cos (0 +Фi)

0.100 = A

therefore Ф = 0

the complete solution is

x = 0.100 cos (3.65 t)

this solution is in meters

Sexual reproduction is the production of a new organism from two parents by making use of their sex cells or gametes. The humans, fish, frogs, cats and dogs, all reproduce by the method of sexual reproduction. I hope this hels :)

Answer:

The work function of the metal is 2.226 eV.

Explanation:

Given;

wavelength of the violet light, λ = 427 nm = 427 x 10⁻⁹ m

maximum kinetic energy, K.E = 0.684 eV

The energy of the incident light is calculated as;

[tex]E = hf = \frac{hc}{\lambda} = \frac{6.626 \ \times \ 10^{-34} \ \times\ 3\ \times \ 10^8 }{427 \ \times \ 10^{-9}} = 4.655 \ \times \ 10^{-19} \ J\\\\1 \ eV = 1.6 \ \times \ 10^{-19} \ J\\\\E =( \frac{4.655 \ \times \ 10^{-19} \ J }{1.6 \ \times \ 10^{-19} \ J} ) \ eV\\\\E = 2.91 \ eV[/tex]

Apply Einstein's photoelectric equation;

E = Ф + K.E

where;

Ф is the work function of the metal

Ф = E - K.E

Ф = 2.91 eV - 0.684 eV

Ф = 2.226 eV.

Therefore, the work function of the metal is 2.226 eV.

Answer:

75km

Explanation:

First we need to understand for how long the battery can work. We can do that by dividing the total distance traveled by the speed of the race car. Since we do have both measurements required we can find the time. And so we get......

[tex]\frac{150km}{100km/hr} = 1.5 hours[/tex]

Now in order to find distance traveled by an object we need to multiply its speed by the time it traveled. Now since we have both of this measurements we can fin the traveling distance. We do ......

[tex]\frac{50km}{1hour}[/tex] x [tex]1.5 hours[/tex] = [tex]75km[/tex]

And just like this we get the answer 75km

Answer:

The valves prevent the backward flow of blood. These valves are actual flaps that are located on each end of the two ventricles (lower chambers of the heart). They act as one-way inlets of blood on one side of a ventricle and one-way outlets of blood on the other side of a ventricle.

Explanation: